Integrand size = 26, antiderivative size = 135 \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=-\frac {3 a^2}{4 b^3 \left (a+b \sqrt [3]{x}\right )^3 \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}}+\frac {2 a}{b^3 \left (a+b \sqrt [3]{x}\right )^2 \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}}-\frac {3}{2 b^3 \left (a+b \sqrt [3]{x}\right ) \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}} \]
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Time = 0.05 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {1355, 660, 45} \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=-\frac {3 a^2}{4 b^3 \left (a+b \sqrt [3]{x}\right )^3 \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}}+\frac {2 a}{b^3 \left (a+b \sqrt [3]{x}\right )^2 \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}}-\frac {3}{2 b^3 \left (a+b \sqrt [3]{x}\right ) \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}} \]
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Rule 45
Rule 660
Rule 1355
Rubi steps \begin{align*} \text {integral}& = 3 \text {Subst}\left (\int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx,x,\sqrt [3]{x}\right ) \\ & = \frac {\left (3 b^5 \left (a+b \sqrt [3]{x}\right )\right ) \text {Subst}\left (\int \frac {x^2}{\left (a b+b^2 x\right )^5} \, dx,x,\sqrt [3]{x}\right )}{\sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}} \\ & = \frac {\left (3 b^5 \left (a+b \sqrt [3]{x}\right )\right ) \text {Subst}\left (\int \left (\frac {a^2}{b^7 (a+b x)^5}-\frac {2 a}{b^7 (a+b x)^4}+\frac {1}{b^7 (a+b x)^3}\right ) \, dx,x,\sqrt [3]{x}\right )}{\sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}} \\ & = -\frac {3 a^2}{4 b^3 \left (a+b \sqrt [3]{x}\right )^3 \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}}+\frac {2 a}{b^3 \left (a+b \sqrt [3]{x}\right )^2 \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}}-\frac {3}{2 b^3 \left (a+b \sqrt [3]{x}\right ) \sqrt {a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}}} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.41 \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=\frac {\left (a+b \sqrt [3]{x}\right ) \left (-a^2-4 a b \sqrt [3]{x}-6 b^2 x^{2/3}\right )}{4 b^3 \left (\left (a+b \sqrt [3]{x}\right )^2\right )^{5/2}} \]
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Time = 0.26 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.32
method | result | size |
derivativedivides | \(-\frac {\left (6 b^{2} x^{\frac {2}{3}}+4 a b \,x^{\frac {1}{3}}+a^{2}\right ) \left (a +b \,x^{\frac {1}{3}}\right )}{4 b^{3} {\left (\left (a +b \,x^{\frac {1}{3}}\right )^{2}\right )}^{\frac {5}{2}}}\) | \(43\) |
default | \(-\frac {\left (6 x^{\frac {22}{3}} b^{22}+45 x^{\frac {20}{3}} a^{2} b^{20}-36 x^{\frac {19}{3}} a^{3} b^{19}+144 x^{\frac {17}{3}} a^{5} b^{17}-189 x^{\frac {16}{3}} a^{6} b^{16}+126 x^{\frac {14}{3}} a^{8} b^{14}-276 x^{\frac {13}{3}} a^{9} b^{13}-36 x^{\frac {11}{3}} a^{11} b^{11}-144 x^{\frac {10}{3}} a^{12} b^{10}-99 x^{\frac {8}{3}} a^{14} b^{8}-20 x^{7} a \,b^{21}-20 a^{4} b^{18} x^{6}-36 x^{\frac {5}{3}} a^{17} b^{5}+120 a^{7} b^{15} x^{5}+15 x^{\frac {4}{3}} a^{18} b^{4}+281 a^{10} b^{12} x^{4}+224 a^{13} b^{9} x^{3}+66 a^{16} b^{6} x^{2}+4 a^{19} b^{3} x +a^{22}\right ) \left (a +b \,x^{\frac {1}{3}}\right )}{4 b^{3} \left (b^{2} x^{\frac {2}{3}}-a b \,x^{\frac {1}{3}}+a^{2}\right )^{4} \left (b^{3} x +a^{3}\right )^{4} \left (a^{2}+2 a b \,x^{\frac {1}{3}}+b^{2} x^{\frac {2}{3}}\right )^{\frac {5}{2}}}\) | \(270\) |
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Time = 0.28 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.01 \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=\frac {20 \, a b^{9} x^{3} - 60 \, a^{4} b^{6} x^{2} - a^{10} - 9 \, {\left (5 \, a^{2} b^{8} x^{2} - 4 \, a^{5} b^{5} x\right )} x^{\frac {2}{3}} - 3 \, {\left (2 \, b^{10} x^{3} - 20 \, a^{3} b^{7} x^{2} + 5 \, a^{6} b^{4} x\right )} x^{\frac {1}{3}}}{4 \, {\left (b^{15} x^{4} + 4 \, a^{3} b^{12} x^{3} + 6 \, a^{6} b^{9} x^{2} + 4 \, a^{9} b^{6} x + a^{12} b^{3}\right )}} \]
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\[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=\int \frac {1}{\left (a^{2} + 2 a b \sqrt [3]{x} + b^{2} x^{\frac {2}{3}}\right )^{\frac {5}{2}}}\, dx \]
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Time = 0.19 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.39 \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=-\frac {3}{2 \, b^{5} {\left (x^{\frac {1}{3}} + \frac {a}{b}\right )}^{2}} + \frac {2 \, a}{b^{6} {\left (x^{\frac {1}{3}} + \frac {a}{b}\right )}^{3}} - \frac {3 \, a^{2}}{4 \, b^{7} {\left (x^{\frac {1}{3}} + \frac {a}{b}\right )}^{4}} \]
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Time = 0.31 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.32 \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=-\frac {6 \, b^{2} x^{\frac {2}{3}} + 4 \, a b x^{\frac {1}{3}} + a^{2}}{4 \, {\left (b x^{\frac {1}{3}} + a\right )}^{4} b^{3} \mathrm {sgn}\left (b x^{\frac {1}{3}} + a\right )} \]
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Time = 9.07 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.39 \[ \int \frac {1}{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^{5/2}} \, dx=-\frac {\sqrt {a^2+b^2\,x^{2/3}+2\,a\,b\,x^{1/3}}\,\left (a^2+6\,b^2\,x^{2/3}+4\,a\,b\,x^{1/3}\right )}{4\,b^3\,{\left (a+b\,x^{1/3}\right )}^5} \]
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